(x^4y^-3)5/x^-3y^2

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Solution for (x^4y^-3)5/x^-3y^2 equation: 


D( x )

x = 0

x^-3 = 0

x = 0

x = 0

x^-3 = 0

x^-3 = 0

1*x^-3 = 0 // : 1

x^-3 = 0

x naleu017Cy do O

x in (-oo:0) U (0:+oo)

(((x^4*y^-3)^5)/(x^-3))*y^2 = 0

x^23*y^-13 = 0 // : y^-13

x^23 = 0

x = 0

x in { 0} 

x belongs to the empty set

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